- reecardmuzzbenchto

# Life Is Feudal: Forest Village V1.1.6641 Vip Hack

print get_verb_i # 0.0395220100000042 A: Use a list comprehension. (i.e. replace the with a { }) L = [3*i for i in L] print(L) Output [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] You can also use math.floor to split your list by 3 and then you can convert it to an int: L = [int(n) for n in (math.floor(i / 3) for i in L)] 2, 4, 6, 10} function foo(vector) local len = #vector for i = 1, len do vector[i] = math.floor(i / 3) end end In the foo function you can specify arguments as an array and use them as array elements. In foo(10, 20, 30) the first argument is a tuple, but that is just how Erlang's syntax works: If a function is of arity n, it is always called with n parameters: each argument is supplied by an actual argument that is the head of a tuple of length n-1. As a side note, I'm not sure that #a is the same as #1: a = a * 10 ?a >?a 1 a #1 3 If you have that problem, Erlang has excellent documentation, but you may need to take some time to study it. I'll be happy to help. Q: How to add attributes to arrays without recreating the array in Python? I want to add additional attributes to an array, but I don't want to recreate the whole array. For example, I have this array a = np.array([[1, 2], [3, 4]]) and I want to add another attribute to it (a.shape = (2,2)) without recreating a new array. How do I achieve this in Python? To append additional attributes to an array, you can use the.copy() method: import numpy as np a = np.array([[1, 2], [3, 4

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